# 50 g of sugar (C12H22O11)is dissolved in 500g water at standard pressure. How much is the boiling point raised

Delta T = Kb x m
m = moles solute / Kg solvent
Molecular weight = 342 g/mol
50 g / 342 = 0.146 moles
m = 0.146 / 0.500 Kg = 0.292
delta T = 0.512 x 0.292 = 0.150 °C
The boiling point will be 100 + 0.150 = 100.150 °C
Data required.

The answers post by the user, for information only, FunQA.com does not guarantee the right.

More Questions and Answers:
• What is the best thermodynamic model to simulate an iso-propy-alcohol and water mixture with t-amyl-alcohol.?
• Help with the following questions/ I'm stuck!!?
• What happens to the mass number of a radioactive isotope during alpha emission?
• Titrating solution X and Y gives me death?
• How do you prepare an ester in the lab using alcohols?
• What is the pressure of gas if 300 ml at 0.8 atm and 37degress C changes to 50 degrees C and 555ml?
• Need chem help.drawing figures?
• What specific solvent can dissolve keratin?
• How many grams in a tablespoon of water?