# 25 ml of 0.5 N NaOH is required to neutralize 30 ml of an unknown acid solution. what is the normality of it?

According to law of equivalence;
milliequivalents of acid = milli equivalents of base
Let N be the normality of the unknown acid.
So N X 30 = 25 X 0.5
Normality = 0.417N
as above N X V for base = N X V for acid
25 x 0.5 = N X 30
N=0.41666
0.4166

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