25 ml of 0.5 N NaOH is required to neutralize 30 ml of an unknown acid solution. what is the normality of it?



Answer:
According to law of equivalence;
milliequivalents of acid = milli equivalents of base
Let N be the normality of the unknown acid.
So N X 30 = 25 X 0.5
Normality = 0.417N
as above N X V for base = N X V for acid
25 x 0.5 = N X 30
N=0.41666
0.4166

The answers post by the user, for information only, FunQA.com does not guarantee the right.



More Questions and Answers:
  • 117-1-Chemistry-4.html
  • What type of energy change occurs when you bake a muffin in a oven?
  • What is thr behavier of Aliphatic compounds?
  • When 20g of glucovanillin(an organic compound found in the green fruit of vanilla) are dissolved in 200g..?
  • What is meant by ‘predicting yield of a commercial ore deposit?
  • What is the product when 1 pentanol is oxidized? What about 2 pentanol?
  • Spa water maintence, anyone help?
  • Agent orange?
  • What experimental procedure could you use to confirm that aqueous sulfuric acid consists of ions, not uncharge