A student required 23.74 mL of NaOh solution to titrate 0.5858 g of HSO3NH2?

What is the molarity of the NaOH solution?

Molecular weight HSO3NH2 = 97 g/mol
0.5858 g / 97 = 0.006039 moles HSO3NH2
NaOH + HSO3NH2 >> SO3NH2+ + Na+ + H2O
Moles MaOH = moles HSO3NH2
M = moles / L 0.006039 / 0.02374 = 0.2544 M ( molarity NaOH)

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