>>> Chemistry Problem <<<?

Calculate the normality of a diluted solution of HCl if its 20ml of normality 10N is mixed with distilled water to make 1dm^3 soln.


Please involve all the steps and 'explain' me what exactly the problem is and how to go about ..


Thank you tonn in advance !!

Answer:
The normality and molarity of HCl are the same as HCl is a monoprotic acid. Since the number of moles of HCl will be the same in the concentrated and the dilulted solution (1 dm^3 = 1 L), then we can set the following equation:

Mconc * Vconc = Mdil * Vdil
Mdil = Mconc * Vconc / Vdil = 10 M * 0.020 L / 1.00 L = 0.20 M = 0.20 N
thats some advanced college stuff..i was reading it to see if i cud help u out, but i cant. sry :( besides, i only took high school chemistry n my teacher wasnt all that good
Surely you mean molarity... or molality?
The normality will be reduced by the ratio of initial solution volume to final solution total volume.

Nf = Ni*Vi/Vt
First of all, in the case of a monoprotic acid like the one we have here, the normality and molarity are the same thing.

Dilution equation:
(MV)initial = (MV)final

1 cubic dm is one liter, which is 1000 mL

(10 M)(20 mL) = M(1000 mL)
M = .2 M = .2 N

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