Consider the reaction Q+R→S+T and the rate law for the reaction rate:rate = k[Q]0[R]2.?

You run the reaction three times with [R] = 2.0M. For each run, you change the starting concentration of [Q] as follows: run 1, [Q] = 0.0M; run 2, [Q] = 1.0M; run 3, [Q] = 2.0M. Rank the rate of the three reactions using each of these concentrations.

Answer:
Since the rate law shows that the reaction is zero order for Q, the starting concentration of Q will not have an effect on the rate. The rates for all 3 runs will be the same, assuming you did not change the concentration of R.

The answers post by the user, for information only, FunQA.com does not guarantee the right.



More Questions and Answers:
  • When you add dry ice to carbonate your homemade root beer, does it react with aluminum?
  • Functional Group Tests -- Procedures?
  • Chemistry Question?
  • When comparing a liquid with a gas at the same temperature which of the following is true?
  • Explain the working of a washing machime?
  • Find the mole fraction of the FeCl2 in the following solution:150 g C6H23O 42.7 g KI 320 g FeCl2 50 g H2O?
  • What is the derivation of molar formula?
  • 1395-Chemistry-4.html
  • Could someone explain to me the effect of amount of surface area on the rate of reaction?