# 7) a gas ocupies 60 L at 250'K and 1 atm. What is the volume at 250'C and 1.5 atm?

please show work

Convert 250 to K – 523K and use combined gas law

V= (523 T1)(1atm P2)(60L V2) / (1.5 atm P1)(250K T2)= 83.6L

Combined gas law:

V1 x P1 / T1 = V2 x P2 / T2

(60 L)(1 atm) / (250 K) = (V2)(1.5 atm) / (523 K)

using Charles's law and Boyle's law

p2*v2*t1=p1*v1*t2

v2 = p1*v1*t2/p2*t1

60L * ( (250K +273K)/250K)) * (1atm/1.5atm)=83.68L

multiply the volume times the (final temp in K / initial temp in K) then multiply that answer by the (initial pressure/final pressure)

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**Answer:**Convert 250 to K – 523K and use combined gas law

V= (523 T1)(1atm P2)(60L V2) / (1.5 atm P1)(250K T2)= 83.6L

Combined gas law:

V1 x P1 / T1 = V2 x P2 / T2

(60 L)(1 atm) / (250 K) = (V2)(1.5 atm) / (523 K)

using Charles's law and Boyle's law

p2*v2*t1=p1*v1*t2

v2 = p1*v1*t2/p2*t1

60L * ( (250K +273K)/250K)) * (1atm/1.5atm)=83.68L

multiply the volume times the (final temp in K / initial temp in K) then multiply that answer by the (initial pressure/final pressure)

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