(5)At what pressure would 100mL of gas be found if it began at 500mL at 2.5 atm?

please show work

P1V1 = P2V2
rearrange to get;
P2 = (P1V1)/V2
plug in the numbers:
P2 = (500ml)(2.5atm)/(100ml)
P2 = 12.5 atm
12.5 atm
Use Boyle's Law to calculate your answer.

P1 x V1 = P2 x V2

P1 = 2.5 atm
V1 = 500 mL
P2 = unknown
V2 = 100 mL
Boyle's Law. Inverse proportion.
Volume decrease <===> Pressure increase.
500mL = 5 x 100mL.
5 x 2.5atm = 12.5atm. = Pressure of 100mL.

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