# (5)At what pressure would 100mL of gas be found if it began at 500mL at 2.5 atm?

please show work

P1V1 = P2V2

rearrange to get;

P2 = (P1V1)/V2

plug in the numbers:

P2 = (500ml)(2.5atm)/(100ml)

P2 = 12.5 atm

12.5 atm

Use Boyle's Law to calculate your answer.

P1 x V1 = P2 x V2

P1 = 2.5 atm

V1 = 500 mL

P2 = unknown

V2 = 100 mL

Boyle's Law. Inverse proportion.

Volume decrease <===> Pressure increase.

500mL = 5 x 100mL.

5 x 2.5atm = 12.5atm. = Pressure of 100mL.

More Questions and Answers:

How can i seperate sugar and salt from water without using any lab apparatus?
Acetic Acid Problem?
What kind of urine test can detect alcohol for up to 3 days.?
Chemistry: BUFFERS?
What are the isotopes?, you must give me a clear answer, good luck!?
Why can't we breathe pure oxygen?
Double Repacement Reactions!?
What is the difference between 2cl & cl2?
I need an example investigatory project any kind of it?

**Answer:**P1V1 = P2V2

rearrange to get;

P2 = (P1V1)/V2

plug in the numbers:

P2 = (500ml)(2.5atm)/(100ml)

P2 = 12.5 atm

12.5 atm

Use Boyle's Law to calculate your answer.

P1 x V1 = P2 x V2

P1 = 2.5 atm

V1 = 500 mL

P2 = unknown

V2 = 100 mL

Boyle's Law. Inverse proportion.

Volume decrease <===> Pressure increase.

500mL = 5 x 100mL.

5 x 2.5atm = 12.5atm. = Pressure of 100mL.

The answers post by the user, for information only, FunQA.com does not guarantee the right.

More Questions and Answers: