# A sample of nitrogen gas occupies 1.55L at 27C and 1.00atm pressure What will the volume be at -100C?

**Answer:**

Charle's Law. Direct proportion. (Pressure constant)

V1 x T2 = V2 x T1

1.55L x -100°C (173K) = V2 x 27°C (300K)

173 ÷ 300 = 0.577

1.55L x 0.577 = 0.894L = 894mL Final volume.

Assuming that the pressure remains the same, the volume will be 1.55 x 173/300 liters.

27C + 273.15 = 300.15K (kelvin)

-100C + 273.15 = 173.15K

P1V1/T1 = P2V2/T2

I'll assume pressure is constant since it wasn't mentioned.

V1/T1 = V2/T2

V1T2/T1 = V2

(1.55L)(173.15K)/(300.15K) = V2

0.894L = V2

V1/V2=T1/T2

1.55L/V=(27+273)K / ( -100+273) K

1.55L/V = 300K / 173 K

V=1.55 L * 173 /300

= 0.894L

u should use t as k not as celsius

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