A compound of vanadium has a magnetic moment 1.73BM. Work out the electronic configuration of vanadium ion.?

A compound of vanadium has a magnetic moment 1.73BM. Work out the electronic configuration of vanadium ion in this compound.
I got unpaired electron as one and figured out that there should be 21 electrons but the answer says 19 electrons. Could any one explain why?

Answer:
1.73 = sqrt(3) = sqrt(n(n+2))

So, n(n+2) = 3

or n = 1

For V, Z = 23, [Ar]4s23d3

Now in V+ it should be [Ar]4s13d3 or 22 electrons
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