210 isotope of the element with atomic #82 undergoes emission of an alpha particle What's the following for it

The 210 isotope of the element with atomic #82 undergoes emission of an alpha particle What's the following for the product?


A-Atomic number?
B-Mass number?
C-Name of the product number?

Answer:
let the element be 82A210
on emission of an alpha particle, its atomic number decreases by 2 & mass number decreases by 4
therefore, the product's
A. atomic number is 80
B. mass number is 206
C. its name is 80B206....it is Hg (mercury)
an alpha particle is 2 protons and 2 neutrons.
hence the atomic number will decrease by 2,making it 80.
the mass number will decrease by 4,making it 206 and hence it will become Mercury-206 written as Hg206(with 206 as superscript).

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