# A sample of gas has an initial volume of 2.45L at a pressure of 855 mm Hg and the temperature of 39 degrees C?

If the gas is heated to a temperture of 116 dgreees C and expandd to a volume of 4.49L, what is its final presure in mmHg

p1 = 855 / 760 = 1.12 atm

T1 = 39 + 273 = 312 K

T2 = 116 + 273 = 389 K

p1V1 = nRT1 >> p1V1 / T1 = nR

p2V2 = nRT2 >> p2V2/ T2 = nR

p1V1 / T1 = p2V2 / T2

1.12 x 2.45 / 312 = p2 x 4.49 / 389

0.00879 = p2 x 0.0115

p2 = 0.761 atm

0.761 x 760 = 578.8 mm Hg

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**Answer:**p1 = 855 / 760 = 1.12 atm

T1 = 39 + 273 = 312 K

T2 = 116 + 273 = 389 K

p1V1 = nRT1 >> p1V1 / T1 = nR

p2V2 = nRT2 >> p2V2/ T2 = nR

p1V1 / T1 = p2V2 / T2

1.12 x 2.45 / 312 = p2 x 4.49 / 389

0.00879 = p2 x 0.0115

p2 = 0.761 atm

0.761 x 760 = 578.8 mm Hg

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