Treating tosylates with NaOH?

If a mixture of cis- and trans-4-t-butylcyclohexyl tosylate is treated with NaOH, is it Sn1 or Sn2? And what would the final composition of cis/trans be (approximately)?

Thanks :)

The rule of thumb of determining whether the reaction undergoes SN1 or SN2 is SN2 requires the back-side attack by the nucleophile so that it detemines by steric hindrance.
In the case of cis and trans-4-t-butylcyclohexyl tosylate, the t-butyl is far away from the leaving group and may not block the attack of OH anion. In addition, a strong nucleophile is used in both reaction. Both reactions undergo SN2.
The product of cis-4-t-butylcyclohexyl tosylate reacted with NaOH is trans-4-t-butylcyclohexanol (back-side attack).
The product of trans-4-t-butylcyclohexyl tosylate reacted with NaOH is cis-4-t-butylcyclohexanol (back-side attack).
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