Calculate the [Pb+2] if the [SO4–2] = 0.0056 M. Ksp = 1 x 10–8?



Answer:
The equilibrium is
PbSO4 <> Pb2+ + SO42-
and the requirement for this equilibrium is that
Ksp = [Pb2+][SO42-]
[Pb2+]= Ksp / [ SO42-] = 1 x 10^-8 /0.056 = 1.79 x 10^-7 M
Ksp=[Pb+2][SO4-2]

1E-8=[Pb+2][0.0056M]
(1E-8)/(0.0056)=[Pb+2]
[Pb+2]=1.2E-6

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