# Any Elec engineers got an answer for this?

Does anyone know how to do this

A circuit having a resistance of 12 ohm, an indutance of 96mH and a capacitance of 52mF in series, is connected across a 220V, 50Hz supply. Calculate the following:

Total Impedance

current flowing through the circuit

the voltage across each component

the phase difference between the current and the supply voltage

The power factor of the circuit

hi

i will answer ure question,,,,,,,,,

firstly ,

note what u are given in the question

R = 12 ohm

L = 96 * 10^-3

C = 52 * 10^-3

V = 220 V

w (frequency) = 50 Hz

==============================...

Total Impedence is denoted by Z

Z = √(XL - XC)^2 + R2

here,

XL is inductive reactance

XL = LW

XL = 96*10^-3*50

Xl = 4.8 ohms

similarly...

XC is capacitive reactance..

XC = 1/CW

XC = 1/52*10^-3*50

XC = 0.3846 ohms

Z = √(XL - XC)^2 + R^2

Z = √ (4.4153)^2 + 144

Z = 12.7863 (by calculator)

so the TOTAL IMPEDENCE IS Z = 12.7863 Ohms

==============================...

ANSWER-2)

Let I be the total current flowing thru the circuit....

V = I * Z

I = V / Z

I = 220/12.7863

I = 17.2059 ampere

so answer is I = 17.2059 ampere

==============================...

ANSWER - 3)

to find the voltage accross the resisitor

we use..

V= I * R

V= 17.2 * 12

V= 206.4 volts

to find the voltage accross a n inductor,,,,,,,,,

we use..

V = I * XL

V=17.2 * 4.8

V= 82.56 volts

to find the volatfe accross a capacitor...

we use...

V= I * XC

V = 17.2 * 0.3846

V = 6.61512 volts

==============================...

ANSWER -4 )

tan (theeta) = (XL - X C) /R

tan (theeta) = 4.4153/12

tan ( theeta) = 0.3679

theeta = tan-1 (0.3679)

this is the phase difference..k

==============================...

ANSWER-5)

Power factor = R / Z

phi is the power factor..

phi = 12/12.7863

phi = 0.9385

this is the power factor......

==============================...

Hope this is the best and most appropriate answer...

all the best....

FunQA.com will not be there to help in your job interview. Grab a book and a calculator.

Given: V=220, f=50hz, L=96millihenry, C=52millifarad

Find: Total Z=impedance

I= current

VL=voltage across inductance

VC=voltage across capacitor

VR=voltage across resistor

theta= phase angle

cos theta= power factor

Formulae:

XL=2pifL, XC=1/2pifC

w=2pif

Z=[(XL-XC)^2+R^2]^0.5

VL=I(XL), VC=I(XC), VR=IR , I=V/Z

Computation:

w=2pif=2(3.1416)50=314.16

XL=wL=314.16(96^-3)=30.159 ohms

XC=1/wC=1/314.16(52^-3)=0.0612 ohms

Z=(30.159-0.0612)^2+12^2]^0.5

=(906.01+144)^.5= 32.4 ohms, total impedance

I=total current=V/Z=220/32.4= 9.876 amps

VL=IXL= 9.876(30.159)= 297.86 volts across inductor

VC=IXC= 9.876(0.06)= 0.592 volts across capacitor

VR=IR= 9.876(12)= 118.512 volts across resistor

phase angle= arctan= (VL-VC)/VR

= (297.86-0.592)/118.512

=2.508

theta= tan^-1=2.508

phase angle=theta= 68.26 deg, voltage to current lag

power factor=cos theta=cos68.26 deg

=0.37 or 37%

hope this is clear enough, good luck

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A circuit having a resistance of 12 ohm, an indutance of 96mH and a capacitance of 52mF in series, is connected across a 220V, 50Hz supply. Calculate the following:

Total Impedance

current flowing through the circuit

the voltage across each component

the phase difference between the current and the supply voltage

The power factor of the circuit

**Answer:**hi

i will answer ure question,,,,,,,,,

firstly ,

note what u are given in the question

R = 12 ohm

L = 96 * 10^-3

C = 52 * 10^-3

V = 220 V

w (frequency) = 50 Hz

==============================...

Total Impedence is denoted by Z

Z = √(XL - XC)^2 + R2

here,

XL is inductive reactance

XL = LW

XL = 96*10^-3*50

Xl = 4.8 ohms

similarly...

XC is capacitive reactance..

XC = 1/CW

XC = 1/52*10^-3*50

XC = 0.3846 ohms

Z = √(XL - XC)^2 + R^2

Z = √ (4.4153)^2 + 144

Z = 12.7863 (by calculator)

so the TOTAL IMPEDENCE IS Z = 12.7863 Ohms

==============================...

ANSWER-2)

Let I be the total current flowing thru the circuit....

V = I * Z

I = V / Z

I = 220/12.7863

I = 17.2059 ampere

so answer is I = 17.2059 ampere

==============================...

ANSWER - 3)

to find the voltage accross the resisitor

we use..

V= I * R

V= 17.2 * 12

V= 206.4 volts

to find the voltage accross a n inductor,,,,,,,,,

we use..

V = I * XL

V=17.2 * 4.8

V= 82.56 volts

to find the volatfe accross a capacitor...

we use...

V= I * XC

V = 17.2 * 0.3846

V = 6.61512 volts

==============================...

ANSWER -4 )

tan (theeta) = (XL - X C) /R

tan (theeta) = 4.4153/12

tan ( theeta) = 0.3679

theeta = tan-1 (0.3679)

this is the phase difference..k

==============================...

ANSWER-5)

Power factor = R / Z

phi is the power factor..

phi = 12/12.7863

phi = 0.9385

this is the power factor......

==============================...

Hope this is the best and most appropriate answer...

all the best....

FunQA.com will not be there to help in your job interview. Grab a book and a calculator.

Given: V=220, f=50hz, L=96millihenry, C=52millifarad

Find: Total Z=impedance

I= current

VL=voltage across inductance

VC=voltage across capacitor

VR=voltage across resistor

theta= phase angle

cos theta= power factor

Formulae:

XL=2pifL, XC=1/2pifC

w=2pif

Z=[(XL-XC)^2+R^2]^0.5

VL=I(XL), VC=I(XC), VR=IR , I=V/Z

Computation:

w=2pif=2(3.1416)50=314.16

XL=wL=314.16(96^-3)=30.159 ohms

XC=1/wC=1/314.16(52^-3)=0.0612 ohms

Z=(30.159-0.0612)^2+12^2]^0.5

=(906.01+144)^.5= 32.4 ohms, total impedance

I=total current=V/Z=220/32.4= 9.876 amps

VL=IXL= 9.876(30.159)= 297.86 volts across inductor

VC=IXC= 9.876(0.06)= 0.592 volts across capacitor

VR=IR= 9.876(12)= 118.512 volts across resistor

phase angle= arctan= (VL-VC)/VR

= (297.86-0.592)/118.512

=2.508

theta= tan^-1=2.508

phase angle=theta= 68.26 deg, voltage to current lag

power factor=cos theta=cos68.26 deg

=0.37 or 37%

hope this is clear enough, good luck

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