# Calculus help!?

A spherical snowball is melting in such a way that its diameter is decreasing at rate of 0.4 cm/min. At what rate is the volume of the snowball decreasing when the diameter is 15 cm. (Note the answer is a positive number).

You'll get better help posting this in the math section.

V = 4/3 π r^3

= 4/3 π (D/2)^3

= π/6 * D^3

dV/dt = π/6 * 3D^2 * dD/dt

= π/6 * 3*(15)^2 * (-0.4)

= -141.4 cm^3 / min

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**Answer:**You'll get better help posting this in the math section.

V = 4/3 π r^3

= 4/3 π (D/2)^3

= π/6 * D^3

dV/dt = π/6 * 3D^2 * dD/dt

= π/6 * 3*(15)^2 * (-0.4)

= -141.4 cm^3 / min

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