# How do you solve a differential equation like this? again, a little different?

d^2y/dx^2+ay/b=0 or d^2y/dx^2+ax/b=0

generally OR for diff eqns does not exist!

♦ Thus y’’=k*y, then y’*y’’ =k*yy’;

then 0.5*(y’^2)’ = 0.5k*(y^2)’,

hence y’ = √(k*y^2 +C1), go on!

♥ thus y’’=kx, then y’=0.5kx^2 +C1, go on!

look up variation of parameters method.

Im a big fan of matlab.

e1='D2y+a*y/b=0'

e2='D2y+a*x/b=0'

y=dsolve(e1,e2,'x')

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**Answer:**generally OR for diff eqns does not exist!

♦ Thus y’’=k*y, then y’*y’’ =k*yy’;

then 0.5*(y’^2)’ = 0.5k*(y^2)’,

hence y’ = √(k*y^2 +C1), go on!

♥ thus y’’=kx, then y’=0.5kx^2 +C1, go on!

look up variation of parameters method.

Im a big fan of matlab.

e1='D2y+a*y/b=0'

e2='D2y+a*x/b=0'

y=dsolve(e1,e2,'x')

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