# A6 – 2a3b3 + b6?

How to factor this??????

Assume A^3 = x and B^3 = y.

The equation then reduces to X^2- 2x*y + y^2

which is equal to (x-y) * (x-y)

Converting x, y into A & B, the answer becomes

(A^3 - B^3) * (A^3 - B^3)

If all else fails use the quadratic equation.

Pretend that a^3 equals x, and that b^3 equals y.

Then, you should recognize!

(a^3 -b^3)^2

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**Answer:**Assume A^3 = x and B^3 = y.

The equation then reduces to X^2- 2x*y + y^2

which is equal to (x-y) * (x-y)

Converting x, y into A & B, the answer becomes

(A^3 - B^3) * (A^3 - B^3)

If all else fails use the quadratic equation.

Pretend that a^3 equals x, and that b^3 equals y.

Then, you should recognize!

(a^3 -b^3)^2

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