# Find the output voltage for the circuit show here?

Find the output voltage for the circuit show here

http://img.photobucket.com/albums/v638/r...

Explain your answer, and show your work. Thanks and good luck :)

Ok, you have a simple series circuit composed of a 10VDC source in series with a 100K and 50K resistor, with your output being taken from the 50K resistor. This is a voltage divider problem.

Vs = 10V

R1 = 100K

R2 = 50K

Vout = VR2

So,

VR2 = Vs(R2/(R1 + R2)) = 10V(50K/(100K + 50K) = 3.33V

Another way you could figure this out would be to find current first, then solve VR2 in terms of V = I * R.

Vs = 10V

R1 = 100K

R2 = 50K

Vout = VR2

I = V/(R1 + R2) = 10V(100K + 50K) = 66.67uA

VR2 = I * R2 = 66.67uA * 50K = 3.33V

Don't cheat. Do your own homework.

Agree, learn for yourself but here's a hint, The resitors in the circuit only impede the current flow. Its a trick question.

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http://img.photobucket.com/albums/v638/r...

Explain your answer, and show your work. Thanks and good luck :)

**Answer:**Ok, you have a simple series circuit composed of a 10VDC source in series with a 100K and 50K resistor, with your output being taken from the 50K resistor. This is a voltage divider problem.

Vs = 10V

R1 = 100K

R2 = 50K

Vout = VR2

So,

VR2 = Vs(R2/(R1 + R2)) = 10V(50K/(100K + 50K) = 3.33V

Another way you could figure this out would be to find current first, then solve VR2 in terms of V = I * R.

Vs = 10V

R1 = 100K

R2 = 50K

Vout = VR2

I = V/(R1 + R2) = 10V(100K + 50K) = 66.67uA

VR2 = I * R2 = 66.67uA * 50K = 3.33V

Don't cheat. Do your own homework.

Agree, learn for yourself but here's a hint, The resitors in the circuit only impede the current flow. Its a trick question.

The answers post by the user, for information only, FunQA.com does not guarantee the right.

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