# 3 phase systems - Generator terminal voltage?

try to solve the following problem.

A series wound generator has an armature resistance of 0.1ohm and field resistance of 0.2ohm respectively

and an induced e.m.f. of 280v

what is its terminal voltage when supplying a load of 100A?

Assuming that the generator was connected in WYE,

dropped voltage across the armature and field is equal to ,

(0.2 + 0.1) x 100 = 30 V

Phase voltage is 280 - 30 = 250 V

Line to line voltage is 250 x sqrt(3) = 433 V

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A series wound generator has an armature resistance of 0.1ohm and field resistance of 0.2ohm respectively

and an induced e.m.f. of 280v

what is its terminal voltage when supplying a load of 100A?

**Answer:**Assuming that the generator was connected in WYE,

dropped voltage across the armature and field is equal to ,

(0.2 + 0.1) x 100 = 30 V

Phase voltage is 280 - 30 = 250 V

Line to line voltage is 250 x sqrt(3) = 433 V

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